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3x+14=13x^2
We move all terms to the left:
3x+14-(13x^2)=0
determiningTheFunctionDomain -13x^2+3x+14=0
a = -13; b = 3; c = +14;
Δ = b2-4ac
Δ = 32-4·(-13)·14
Δ = 737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{737}}{2*-13}=\frac{-3-\sqrt{737}}{-26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{737}}{2*-13}=\frac{-3+\sqrt{737}}{-26} $
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