3x+15-6x+18=12x+36

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Solution for 3x+15-6x+18=12x+36 equation: 



3x+15-6x+18=12x+36

We move all terms to the left:

3x+15-6x+18-(12x+36)=0

We add all the numbers together, and all the variables

-3x-(12x+36)+33=0

We get rid of parentheses

-3x-12x-36+33=0

We add all the numbers together, and all the variables

-15x-3=0

We move all terms containing x to the left, all other terms to the right

-15x=3

x=3/-15

x=-1/5

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