3x+15=(34+x)+3

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Solution for 3x+15=(34+x)+3 equation: 



3x+15=(34+x)+3

We move all terms to the left:

3x+15-((34+x)+3)=0

We add all the numbers together, and all the variables

3x-((x+34)+3)+15=0



We calculate terms in parentheses: -((x+34)+3), so:

(x+34)+3

We get rid of parentheses

x+34+3

We add all the numbers together, and all the variables

x+37

Back to the equation:

-(x+37)



We get rid of parentheses

3x-x-37+15=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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