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3x+15=2(x+2)+x+11
We move all terms to the left:
3x+15-(2(x+2)+x+11)=0
We calculate terms in parentheses: -(2(x+2)+x+11), so:We get rid of parentheses
2(x+2)+x+11
We add all the numbers together, and all the variables
x+2(x+2)+11
We multiply parentheses
x+2x+4+11
We add all the numbers together, and all the variables
3x+15
Back to the equation:
-(3x+15)
3x-3x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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