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3x+17-1/2x-5=180
We move all terms to the left:
3x+17-1/2x-5-(180)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x-1/2x-168=0
We multiply all the terms by the denominator
3x*2x-168*2x-1=0
Wy multiply elements
6x^2-336x-1=0
a = 6; b = -336; c = -1;
Δ = b2-4ac
Δ = -3362-4·6·(-1)
Δ = 112920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112920}=\sqrt{4*28230}=\sqrt{4}*\sqrt{28230}=2\sqrt{28230}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-336)-2\sqrt{28230}}{2*6}=\frac{336-2\sqrt{28230}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-336)+2\sqrt{28230}}{2*6}=\frac{336+2\sqrt{28230}}{12} $
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