3x+17=(2x-5)+(x+40)

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Solution for 3x+17=(2x-5)+(x+40) equation: 



3x+17=(2x-5)+(x+40)

We move all terms to the left:

3x+17-((2x-5)+(x+40))=0



We calculate terms in parentheses: -((2x-5)+(x+40)), so:

(2x-5)+(x+40)

We get rid of parentheses

2x+x-5+40

We add all the numbers together, and all the variables

3x+35

Back to the equation:

-(3x+35)



We get rid of parentheses

3x-3x-35+17=0

We add all the numbers together, and all the variables

-18!=0

There is no solution for this equation

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