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3x+17=(2x-5)+(x+40)
We move all terms to the left:
3x+17-((2x-5)+(x+40))=0
We calculate terms in parentheses: -((2x-5)+(x+40)), so:We get rid of parentheses
(2x-5)+(x+40)
We get rid of parentheses
2x+x-5+40
We add all the numbers together, and all the variables
3x+35
Back to the equation:
-(3x+35)
3x-3x-35+17=0
We add all the numbers together, and all the variables
-18!=0
There is no solution for this equation
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