3x+19+2x=3(x+3)

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Solution for 3x+19+2x=3(x+3) equation: 



3x+19+2x=3(x+3)

We move all terms to the left:

3x+19+2x-(3(x+3))=0

We add all the numbers together, and all the variables

5x-(3(x+3))+19=0



We calculate terms in parentheses: -(3(x+3)), so:

3(x+3)

We multiply parentheses

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

5x-3x-9+19=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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