3x+19=2(3x+2)+6

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Solution for 3x+19=2(3x+2)+6 equation: 



3x+19=2(3x+2)+6

We move all terms to the left:

3x+19-(2(3x+2)+6)=0



We calculate terms in parentheses: -(2(3x+2)+6), so:

2(3x+2)+6

We multiply parentheses

6x+4+6

We add all the numbers together, and all the variables

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

3x-6x-10+19=0

We add all the numbers together, and all the variables

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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