3x+1=(7x-3)2

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Solution for 3x+1=(7x-3)2 equation: 



3x+1=(7x-3)2

We move all terms to the left:

3x+1-((7x-3)2)=0



We calculate terms in parentheses: -((7x-3)2), so:

(7x-3)2

We multiply parentheses

14x-6

Back to the equation:

-(14x-6)



We get rid of parentheses

3x-14x+6+1=0

We add all the numbers together, and all the variables

-11x+7=0

We move all terms containing x to the left, all other terms to the right

-11x=-7

x=-7/-11

x=7/11

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