3x+1=(8x-2)-(4x+6)

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Solution for 3x+1=(8x-2)-(4x+6) equation: 



3x+1=(8x-2)-(4x+6)

We move all terms to the left:

3x+1-((8x-2)-(4x+6))=0



We calculate terms in parentheses: -((8x-2)-(4x+6)), so:

(8x-2)-(4x+6)

We get rid of parentheses

8x-4x-2-6

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

3x-4x+8+1=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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