3x+1=2(1+3x)+19

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Solution for 3x+1=2(1+3x)+19 equation: 



3x+1=2(1+3x)+19

We move all terms to the left:

3x+1-(2(1+3x)+19)=0

We add all the numbers together, and all the variables

3x-(2(3x+1)+19)+1=0



We calculate terms in parentheses: -(2(3x+1)+19), so:

2(3x+1)+19

We multiply parentheses

6x+2+19

We add all the numbers together, and all the variables

6x+21

Back to the equation:

-(6x+21)



We get rid of parentheses

3x-6x-21+1=0

We add all the numbers together, and all the variables

-3x-20=0

We move all terms containing x to the left, all other terms to the right

-3x=20

x=20/-3

x=-6+2/3

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