3x+1=2(3x+3)

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Solution for 3x+1=2(3x+3) equation: 



3x+1=2(3x+3)

We move all terms to the left:

3x+1-(2(3x+3))=0



We calculate terms in parentheses: -(2(3x+3)), so:

2(3x+3)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

3x-6x-6+1=0

We add all the numbers together, and all the variables

-3x-5=0

We move all terms containing x to the left, all other terms to the right

-3x=5

x=5/-3

x=-1+2/3

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