3x+1=3(x-1)+4

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Solution for 3x+1=3(x-1)+4 equation: 


Simplifying
3x + 1 = 3(x + -1) + 4

Reorder the terms:
1 + 3x = 3(x + -1) + 4

Reorder the terms:
1 + 3x = 3(-1 + x) + 4
1 + 3x = (-1 * 3 + x * 3) + 4
1 + 3x = (-3 + 3x) + 4

Reorder the terms:
1 + 3x = -3 + 4 + 3x

Combine like terms: -3 + 4 = 1
1 + 3x = 1 + 3x

Add '-1' to each side of the equation.
1 + -1 + 3x = 1 + -1 + 3x

Combine like terms: 1 + -1 = 0
0 + 3x = 1 + -1 + 3x
3x = 1 + -1 + 3x

Combine like terms: 1 + -1 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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