3x+1=4(4x-3)

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Solution for 3x+1=4(4x-3) equation: 



3x+1=4(4x-3)

We move all terms to the left:

3x+1-(4(4x-3))=0



We calculate terms in parentheses: -(4(4x-3)), so:

4(4x-3)

We multiply parentheses

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

3x-16x+12+1=0

We add all the numbers together, and all the variables

-13x+13=0

We move all terms containing x to the left, all other terms to the right

-13x=-13

x=-13/-13

x=1

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