3x+1=5(x-1)-2(7-2x)

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Solution for 3x+1=5(x-1)-2(7-2x) equation: 



3x+1=5(x-1)-2(7-2x)

We move all terms to the left:

3x+1-(5(x-1)-2(7-2x))=0

We add all the numbers together, and all the variables

3x-(5(x-1)-2(-2x+7))+1=0



We calculate terms in parentheses: -(5(x-1)-2(-2x+7)), so:

5(x-1)-2(-2x+7)

We multiply parentheses

5x+4x-5-14

We add all the numbers together, and all the variables

9x-19

Back to the equation:

-(9x-19)



We get rid of parentheses

3x-9x+19+1=0

We add all the numbers together, and all the variables

-6x+20=0

We move all terms containing x to the left, all other terms to the right

-6x=-20

x=-20/-6

x=3+1/3

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