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3x+1=5-x+4(x-1)
We move all terms to the left:
3x+1-(5-x+4(x-1))=0
We calculate terms in parentheses: -(5-x+4(x-1)), so:We get rid of parentheses
5-x+4(x-1)
determiningTheFunctionDomain -x+4(x-1)+5
We add all the numbers together, and all the variables
-1x+4(x-1)+5
We multiply parentheses
-1x+4x-4+5
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
3x-3x-1+1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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