3x+1=7+3(x-2)

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Solution for 3x+1=7+3(x-2) equation: 



3x+1=7+3(x-2)

We move all terms to the left:

3x+1-(7+3(x-2))=0



We calculate terms in parentheses: -(7+3(x-2)), so:

7+3(x-2)

determiningTheFunctionDomain
3(x-2)+7

We multiply parentheses

3x-6+7

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

3x-3x-1+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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