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3x+1=x-2(2-x)
We move all terms to the left:
3x+1-(x-2(2-x))=0
We add all the numbers together, and all the variables
3x-(x-2(-1x+2))+1=0
We calculate terms in parentheses: -(x-2(-1x+2)), so:We get rid of parentheses
x-2(-1x+2)
We multiply parentheses
x+2x-4
We add all the numbers together, and all the variables
3x-4
Back to the equation:
-(3x-4)
3x-3x+4+1=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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