3x+2(2x+4)=78

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Solution for 3x+2(2x+4)=78 equation: 



3x+2(2x+4)=78

We move all terms to the left:

3x+2(2x+4)-(78)=0

We multiply parentheses

3x+4x+8-78=0

We add all the numbers together, and all the variables

7x-70=0

We move all terms containing x to the left, all other terms to the right

7x=70

x=70/7

x=10

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