3x+2(2x-5)=4(x-2)-1

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Solution for 3x+2(2x-5)=4(x-2)-1 equation: 



3x+2(2x-5)=4(x-2)-1

We move all terms to the left:

3x+2(2x-5)-(4(x-2)-1)=0

We multiply parentheses

3x+4x-(4(x-2)-1)-10=0



We calculate terms in parentheses: -(4(x-2)-1), so:

4(x-2)-1

We multiply parentheses

4x-8-1

We add all the numbers together, and all the variables

4x-9

Back to the equation:

-(4x-9)



We add all the numbers together, and all the variables

7x-(4x-9)-10=0

We get rid of parentheses

7x-4x+9-10=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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