3x+2(2x-62)+1(2x-22)=863

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Solution for 3x+2(2x-62)+1(2x-22)=863 equation:



3x+2(2x-62)+1(2x-22)=863
We move all terms to the left:
3x+2(2x-62)+1(2x-22)-(863)=0
We multiply parentheses
3x+4x+1(2x-22)-124-863=0
We add all the numbers together, and all the variables
7x+1(2x-22)-987=0
We move all terms containing x to the left, all other terms to the right
7x+1(2x-22)=987

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