3x+2(4x+2)2=(6x+1)

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Solution for 3x+2(4x+2)2=(6x+1) equation: 



3x+2(4x+2)2=(6x+1)

We move all terms to the left:

3x+2(4x+2)2-((6x+1))=0

We multiply parentheses

3x+16x-((6x+1))+8=0



We calculate terms in parentheses: -((6x+1)), so:

(6x+1)

We get rid of parentheses

6x+1

Back to the equation:

-(6x+1)



We add all the numbers together, and all the variables

19x-(6x+1)+8=0

We get rid of parentheses

19x-6x-1+8=0

We add all the numbers together, and all the variables

13x+7=0

We move all terms containing x to the left, all other terms to the right

13x=-7

x=-7/13

x=-7/13

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