3x+2(5x-4x)+3=-3(2x+3)-10x

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Solution for 3x+2(5x-4x)+3=-3(2x+3)-10x equation: 



3x+2(5x-4x)+3=-3(2x+3)-10x

We move all terms to the left:

3x+2(5x-4x)+3-(-3(2x+3)-10x)=0

We add all the numbers together, and all the variables

3x+2(+x)-(-3(2x+3)-10x)+3=0

We multiply parentheses

3x+2x-(-3(2x+3)-10x)+3=0



We calculate terms in parentheses: -(-3(2x+3)-10x), so:

-3(2x+3)-10x

We add all the numbers together, and all the variables

-10x-3(2x+3)

We multiply parentheses

-10x-6x-9

We add all the numbers together, and all the variables

-16x-9

Back to the equation:

-(-16x-9)



We add all the numbers together, and all the variables

5x-(-16x-9)+3=0

We get rid of parentheses

5x+16x+9+3=0

We add all the numbers together, and all the variables

21x+12=0

We move all terms containing x to the left, all other terms to the right

21x=-12

x=-12/21

x=-4/7

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