3x+2(6x-3)=42

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Solution for 3x+2(6x-3)=42 equation: 



3x+2(6x-3)=42

We move all terms to the left:

3x+2(6x-3)-(42)=0

We multiply parentheses

3x+12x-6-42=0

We add all the numbers together, and all the variables

15x-48=0

We move all terms containing x to the left, all other terms to the right

15x=48

x=48/15

x=3+1/5

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