3x+2(x+1)+3(x+2)=8

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Solution for 3x+2(x+1)+3(x+2)=8 equation: 


Simplifying
3x + 2(x + 1) + 3(x + 2) = 8

Reorder the terms:
3x + 2(1 + x) + 3(x + 2) = 8
3x + (1 * 2 + x * 2) + 3(x + 2) = 8
3x + (2 + 2x) + 3(x + 2) = 8

Reorder the terms:
3x + 2 + 2x + 3(2 + x) = 8
3x + 2 + 2x + (2 * 3 + x * 3) = 8
3x + 2 + 2x + (6 + 3x) = 8

Reorder the terms:
2 + 6 + 3x + 2x + 3x = 8

Combine like terms: 2 + 6 = 8
8 + 3x + 2x + 3x = 8

Combine like terms: 3x + 2x = 5x
8 + 5x + 3x = 8

Combine like terms: 5x + 3x = 8x
8 + 8x = 8

Add '-8' to each side of the equation.
8 + -8 + 8x = 8 + -8

Combine like terms: 8 + -8 = 0
0 + 8x = 8 + -8
8x = 8 + -8

Combine like terms: 8 + -8 = 0
8x = 0

Solving
8x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '8'.
x = 0

Simplifying
x = 0

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