3x+2(x+2)=22-3(2x-1)

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Solution for 3x+2(x+2)=22-3(2x-1) equation: 



3x+2(x+2)=22-3(2x-1)

We move all terms to the left:

3x+2(x+2)-(22-3(2x-1))=0

We multiply parentheses

3x+2x-(22-3(2x-1))+4=0



We calculate terms in parentheses: -(22-3(2x-1)), so:

22-3(2x-1)

determiningTheFunctionDomain
-3(2x-1)+22

We multiply parentheses

-6x+3+22

We add all the numbers together, and all the variables

-6x+25

Back to the equation:

-(-6x+25)



We add all the numbers together, and all the variables

5x-(-6x+25)+4=0

We get rid of parentheses

5x+6x-25+4=0

We add all the numbers together, and all the variables

11x-21=0

We move all terms containing x to the left, all other terms to the right

11x=21

x=21/11

x=1+10/11

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