3x+2(x+2)=22-3(2x-5)

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Solution for 3x+2(x+2)=22-3(2x-5) equation: 



3x+2(x+2)=22-3(2x-5)

We move all terms to the left:

3x+2(x+2)-(22-3(2x-5))=0

We multiply parentheses

3x+2x-(22-3(2x-5))+4=0



We calculate terms in parentheses: -(22-3(2x-5)), so:

22-3(2x-5)

determiningTheFunctionDomain
-3(2x-5)+22

We multiply parentheses

-6x+15+22

We add all the numbers together, and all the variables

-6x+37

Back to the equation:

-(-6x+37)



We add all the numbers together, and all the variables

5x-(-6x+37)+4=0

We get rid of parentheses

5x+6x-37+4=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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