3x+2(x+3)=20-(2x-5)

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Solution for 3x+2(x+3)=20-(2x-5) equation: 



3x+2(x+3)=20-(2x-5)

We move all terms to the left:

3x+2(x+3)-(20-(2x-5))=0

We multiply parentheses

3x+2x-(20-(2x-5))+6=0



We calculate terms in parentheses: -(20-(2x-5)), so:

20-(2x-5)

determiningTheFunctionDomain
-(2x-5)+20

We get rid of parentheses

-2x+5+20

We add all the numbers together, and all the variables

-2x+25

Back to the equation:

-(-2x+25)



We add all the numbers together, and all the variables

5x-(-2x+25)+6=0

We get rid of parentheses

5x+2x-25+6=0

We add all the numbers together, and all the variables

7x-19=0

We move all terms containing x to the left, all other terms to the right

7x=19

x=19/7

x=2+5/7

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