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3x+2(x+4)=5(x+1)
We move all terms to the left:
3x+2(x+4)-(5(x+1))=0
We multiply parentheses
3x+2x-(5(x+1))+8=0
We calculate terms in parentheses: -(5(x+1)), so:We add all the numbers together, and all the variables
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
5x-(5x+5)+8=0
We get rid of parentheses
5x-5x-5+8=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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