3x+2(x+4)=5(x+4)-38

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Solution for 3x+2(x+4)=5(x+4)-38 equation:


Simplifying
3x + 2(x + 4) = 5(x + 4) + -38

Reorder the terms:
3x + 2(4 + x) = 5(x + 4) + -38
3x + (4 * 2 + x * 2) = 5(x + 4) + -38
3x + (8 + 2x) = 5(x + 4) + -38

Reorder the terms:
8 + 3x + 2x = 5(x + 4) + -38

Combine like terms: 3x + 2x = 5x
8 + 5x = 5(x + 4) + -38

Reorder the terms:
8 + 5x = 5(4 + x) + -38
8 + 5x = (4 * 5 + x * 5) + -38
8 + 5x = (20 + 5x) + -38

Reorder the terms:
8 + 5x = 20 + -38 + 5x

Combine like terms: 20 + -38 = -18
8 + 5x = -18 + 5x

Add '-5x' to each side of the equation.
8 + 5x + -5x = -18 + 5x + -5x

Combine like terms: 5x + -5x = 0
8 + 0 = -18 + 5x + -5x
8 = -18 + 5x + -5x

Combine like terms: 5x + -5x = 0
8 = -18 + 0
8 = -18

Solving
8 = -18

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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