3x+2(x+5)-3(x+4)=3(2x-4)-(5x+4)+19

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Solution for 3x+2(x+5)-3(x+4)=3(2x-4)-(5x+4)+19 equation:



3x+2(x+5)-3(x+4)=3(2x-4)-(5x+4)+19
We move all terms to the left:
3x+2(x+5)-3(x+4)-(3(2x-4)-(5x+4)+19)=0
We multiply parentheses
3x+2x-3x-(3(2x-4)-(5x+4)+19)+10-12=0
We calculate terms in parentheses: -(3(2x-4)-(5x+4)+19), so:
3(2x-4)-(5x+4)+19
We multiply parentheses
6x-(5x+4)-12+19
We get rid of parentheses
6x-5x-4-12+19
We add all the numbers together, and all the variables
x+3
Back to the equation:
-(x+3)
We add all the numbers together, and all the variables
2x-(x+3)-2=0
We get rid of parentheses
2x-x-3-2=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5

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