3x+2(x+7)=7(x+3)+1

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Solution for 3x+2(x+7)=7(x+3)+1 equation: 



3x+2(x+7)=7(x+3)+1

We move all terms to the left:

3x+2(x+7)-(7(x+3)+1)=0

We multiply parentheses

3x+2x-(7(x+3)+1)+14=0



We calculate terms in parentheses: -(7(x+3)+1), so:

7(x+3)+1

We multiply parentheses

7x+21+1

We add all the numbers together, and all the variables

7x+22

Back to the equation:

-(7x+22)



We add all the numbers together, and all the variables

5x-(7x+22)+14=0

We get rid of parentheses

5x-7x-22+14=0

We add all the numbers together, and all the variables

-2x-8=0

We move all terms containing x to the left, all other terms to the right

-2x=8

x=8/-2

x=-4

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