3x+2(x-1)=4(x+3)

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Solution for 3x+2(x-1)=4(x+3) equation: 



3x+2(x-1)=4(x+3)

We move all terms to the left:

3x+2(x-1)-(4(x+3))=0

We multiply parentheses

3x+2x-(4(x+3))-2=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

5x-(4x+12)-2=0

We get rid of parentheses

5x-4x-12-2=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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