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3x+2(x-1)=5-2(3-x)
We move all terms to the left:
3x+2(x-1)-(5-2(3-x))=0
We add all the numbers together, and all the variables
3x+2(x-1)-(5-2(-1x+3))=0
We multiply parentheses
3x+2x-(5-2(-1x+3))-2=0
We calculate terms in parentheses: -(5-2(-1x+3)), so:We add all the numbers together, and all the variables
5-2(-1x+3)
determiningTheFunctionDomain -2(-1x+3)+5
We multiply parentheses
2x-6+5
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
5x-(2x-1)-2=0
We get rid of parentheses
5x-2x+1-2=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3
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