3x+2(x-2)+x+1=2x-3+3(x+4)

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Solution for 3x+2(x-2)+x+1=2x-3+3(x+4) equation: 



3x+2(x-2)+x+1=2x-3+3(x+4)

We move all terms to the left:

3x+2(x-2)+x+1-(2x-3+3(x+4))=0

We add all the numbers together, and all the variables

4x+2(x-2)-(2x-3+3(x+4))+1=0

We multiply parentheses

4x+2x-(2x-3+3(x+4))-4+1=0



We calculate terms in parentheses: -(2x-3+3(x+4)), so:

2x-3+3(x+4)

determiningTheFunctionDomain
2x+3(x+4)-3

We multiply parentheses

2x+3x+12-3

We add all the numbers together, and all the variables

5x+9

Back to the equation:

-(5x+9)



We add all the numbers together, and all the variables

6x-(5x+9)-3=0

We get rid of parentheses

6x-5x-9-3=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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