3x+2(x-3)=64

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Solution for 3x+2(x-3)=64 equation: 



3x+2(x-3)=64

We move all terms to the left:

3x+2(x-3)-(64)=0

We multiply parentheses

3x+2x-6-64=0

We add all the numbers together, and all the variables

5x-70=0

We move all terms containing x to the left, all other terms to the right

5x=70

x=70/5

x=14

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