3x+2(x-4)-4(13-2x)=(6x-3)(-2)+3x

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Solution for 3x+2(x-4)-4(13-2x)=(6x-3)(-2)+3x equation: 



3x+2(x-4)-4(13-2x)=(6x-3)(-2)+3x

We move all terms to the left:

3x+2(x-4)-4(13-2x)-((6x-3)(-2)+3x)=0

We add all the numbers together, and all the variables

3x+2(x-4)-4(-2x+13)-((6x-3)(-2)+3x)=0

We multiply parentheses

3x+2x+8x-((6x-3)(-2)+3x)-8-52=0

We multiply parentheses ..

3x+2x+8x-((-12x+6)+3x)-8-52=0



We calculate terms in parentheses: -((-12x+6)+3x), so:

(-12x+6)+3x

We add all the numbers together, and all the variables

3x+(-12x+6)

We get rid of parentheses

3x-12x+6

We add all the numbers together, and all the variables

-9x+6

Back to the equation:

-(-9x+6)



We add all the numbers together, and all the variables

13x-(-9x+6)-60=0

We get rid of parentheses

13x+9x-6-60=0

We add all the numbers together, and all the variables

22x-66=0

We move all terms containing x to the left, all other terms to the right

22x=66

x=66/22

x=3

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