3x+2(x-4)=-8(x+1)

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Solution for 3x+2(x-4)=-8(x+1) equation: 



3x+2(x-4)=-8(x+1)

We move all terms to the left:

3x+2(x-4)-(-8(x+1))=0

We multiply parentheses

3x+2x-(-8(x+1))-8=0



We calculate terms in parentheses: -(-8(x+1)), so:

-8(x+1)

We multiply parentheses

-8x-8

Back to the equation:

-(-8x-8)



We add all the numbers together, and all the variables

5x-(-8x-8)-8=0

We get rid of parentheses

5x+8x+8-8=0

We add all the numbers together, and all the variables

13x=0

x=0/13

x=0

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