3x+2(x-4)=9x-2(x+7)+2(3-x)

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Solution for 3x+2(x-4)=9x-2(x+7)+2(3-x) equation: 



3x+2(x-4)=9x-2(x+7)+2(3-x)

We move all terms to the left:

3x+2(x-4)-(9x-2(x+7)+2(3-x))=0

We add all the numbers together, and all the variables

3x+2(x-4)-(9x-2(x+7)+2(-1x+3))=0

We multiply parentheses

3x+2x-(9x-2(x+7)+2(-1x+3))-8=0



We calculate terms in parentheses: -(9x-2(x+7)+2(-1x+3)), so:

9x-2(x+7)+2(-1x+3)

We multiply parentheses

9x-2x-2x-14+6

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We add all the numbers together, and all the variables

5x-(5x-8)-8=0

We get rid of parentheses

5x-5x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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