3x+2(x-4)=x+4(x-2)

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Solution for 3x+2(x-4)=x+4(x-2) equation:


Simplifying
3x + 2(x + -4) = x + 4(x + -2)

Reorder the terms:
3x + 2(-4 + x) = x + 4(x + -2)
3x + (-4 * 2 + x * 2) = x + 4(x + -2)
3x + (-8 + 2x) = x + 4(x + -2)

Reorder the terms:
-8 + 3x + 2x = x + 4(x + -2)

Combine like terms: 3x + 2x = 5x
-8 + 5x = x + 4(x + -2)

Reorder the terms:
-8 + 5x = x + 4(-2 + x)
-8 + 5x = x + (-2 * 4 + x * 4)
-8 + 5x = x + (-8 + 4x)

Reorder the terms:
-8 + 5x = -8 + x + 4x

Combine like terms: x + 4x = 5x
-8 + 5x = -8 + 5x

Add '8' to each side of the equation.
-8 + 8 + 5x = -8 + 8 + 5x

Combine like terms: -8 + 8 = 0
0 + 5x = -8 + 8 + 5x
5x = -8 + 8 + 5x

Combine like terms: -8 + 8 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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