3x+2(x-5)+10=23(9x-15)+4x

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Solution for 3x+2(x-5)+10=23(9x-15)+4x equation: 



3x+2(x-5)+10=23(9x-15)+4x

We move all terms to the left:

3x+2(x-5)+10-(23(9x-15)+4x)=0

We multiply parentheses

3x+2x-(23(9x-15)+4x)-10+10=0



We calculate terms in parentheses: -(23(9x-15)+4x), so:

23(9x-15)+4x

We add all the numbers together, and all the variables

4x+23(9x-15)

We multiply parentheses

4x+207x-345

We add all the numbers together, and all the variables

211x-345

Back to the equation:

-(211x-345)



We add all the numbers together, and all the variables

5x-(211x-345)=0

We get rid of parentheses

5x-211x+345=0

We add all the numbers together, and all the variables

-206x+345=0

We move all terms containing x to the left, all other terms to the right

-206x=-345

x=-345/-206

x=1+139/206

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