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3x+2(x-5)=1x-12
We move all terms to the left:
3x+2(x-5)-(1x-12)=0
We add all the numbers together, and all the variables
3x+2(x-5)-(x-12)=0
We multiply parentheses
3x+2x-(x-12)-10=0
We get rid of parentheses
3x+2x-x+12-10=0
We add all the numbers together, and all the variables
4x+2=0
We move all terms containing x to the left, all other terms to the right
4x=-2
x=-2/4
x=-1/2
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