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3x+2(x-5)=5(x-2)
We move all terms to the left:
3x+2(x-5)-(5(x-2))=0
We multiply parentheses
3x+2x-(5(x-2))-10=0
We calculate terms in parentheses: -(5(x-2)), so:We add all the numbers together, and all the variables
5(x-2)
We multiply parentheses
5x-10
Back to the equation:
-(5x-10)
5x-(5x-10)-10=0
We get rid of parentheses
5x-5x+10-10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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