3x+2+3=3(x+1)-2

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Solution for 3x+2+3=3(x+1)-2 equation: 



3x+2+3=3(x+1)-2

We move all terms to the left:

3x+2+3-(3(x+1)-2)=0

We add all the numbers together, and all the variables

3x-(3(x+1)-2)+5=0



We calculate terms in parentheses: -(3(x+1)-2), so:

3(x+1)-2

We multiply parentheses

3x+3-2

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

3x-3x-1+5=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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