3x+2+x=(x+1)-2

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Solution for 3x+2+x=(x+1)-2 equation: 



3x+2+x=(x+1)-2

We move all terms to the left:

3x+2+x-((x+1)-2)=0

We add all the numbers together, and all the variables

4x-((x+1)-2)+2=0



We calculate terms in parentheses: -((x+1)-2), so:

(x+1)-2

We get rid of parentheses

x+1-2

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)



We get rid of parentheses

4x-x+1+2=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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