3x+2-3(x+4)-x=3(x+4)-10

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Solution for 3x+2-3(x+4)-x=3(x+4)-10 equation: 



3x+2-3(x+4)-x=3(x+4)-10

We move all terms to the left:

3x+2-3(x+4)-x-(3(x+4)-10)=0

We add all the numbers together, and all the variables

2x-3(x+4)-(3(x+4)-10)+2=0

We multiply parentheses

2x-3x-(3(x+4)-10)-12+2=0



We calculate terms in parentheses: -(3(x+4)-10), so:

3(x+4)-10

We multiply parentheses

3x+12-10

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

-1x-(3x+2)-10=0

We get rid of parentheses

-1x-3x-2-10=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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