3x+2-4x=8-2(x+3)

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Solution for 3x+2-4x=8-2(x+3) equation: 



3x+2-4x=8-2(x+3)

We move all terms to the left:

3x+2-4x-(8-2(x+3))=0

We add all the numbers together, and all the variables

-1x-(8-2(x+3))+2=0



We calculate terms in parentheses: -(8-2(x+3)), so:

8-2(x+3)

determiningTheFunctionDomain
-2(x+3)+8

We multiply parentheses

-2x-6+8

We add all the numbers together, and all the variables

-2x+2

Back to the equation:

-(-2x+2)



We get rid of parentheses

-1x+2x-2+2=0

We add all the numbers together, and all the variables

x=0

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