3x+2/2x+3=6x+7/4x+5

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Solution for 3x+2/2x+3=6x+7/4x+5 equation: 



3x+2/2x+3=6x+7/4x+5

We move all terms to the left:

3x+2/2x+3-(6x+7/4x+5)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 4x+5)!=0

x∈R



We get rid of parentheses

3x+2/2x-6x-7/4x-5+3=0

We calculate fractions


3x-6x+8x/8x^2+(-14x)/8x^2-5+3=0

We add all the numbers together, and all the variables

-3x+8x/8x^2+(-14x)/8x^2-2=0

We multiply all the terms by the denominator


-3x*8x^2+8x+(-14x)-2*8x^2=0

We add all the numbers together, and all the variables

8x-3x*8x^2+(-14x)-2*8x^2=0

Wy multiply elements

-24x^3-16x^2+8x+(-14x)=0

We get rid of parentheses

-24x^3-16x^2+8x-14x=0

We do not support expression: x^3

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