3x+2/2x-1=x-12/x+6

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Solution for 3x+2/2x-1=x-12/x+6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+(2/2)*x-1 = x-(12/x)+6 // - x-(12/x)+6

3*x+(2/2)*x-x+12/x-6-1 = 0

3*x^1+12*x^-1-7*x^0 = 0

(3*x^2-7*x^1+12*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-7*x^1+12*x^0) = 0

x^1

3*x^2-7*x+12 = 0

3*x^2-7*x+12 = 0

DELTA = (-7)^2-(3*4*12)

DELTA = -95

DELTA < 0

x in { } 

x belongs to the empty set

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