3x+2/2x-3=x-4/x-6

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Solution for 3x+2/2x-3=x-4/x-6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+(2/2)*x-3 = x-(4/x)-6 // - x-(4/x)-6

3*x+(2/2)*x-x+4/x-3+6 = 0

3*x^1+4*x^-1+3*x^0 = 0

(3*x^2+3*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2+3*x^1+4*x^0) = 0

x^1

3*x^2+3*x+4 = 0

3*x^2+3*x+4 = 0

DELTA = 3^2-(3*4*4)

DELTA = -39

DELTA < 0

x in { } 

x belongs to the empty set

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